Systems. Methods. Technologies 1 (37) 2018

Системы Методы Технологии. Ю.Н. Алпатов и др. Декомпозиция передаточной … 2018 № 1 (37) с. 65-71 69 1) 1)( ( 1) ( 1 1 1 1 1 1 1 1 1 1 2 + + + −+ = + − + = − = ∑ ST TS TS k ST ST k TS WW W . Произведем проверку вычислений: 1) ( 1 1) 1)( ( 1) ( 1 1) ( 1) 1)( ( 1) ( 1 1 1 1 1 1 1 1 1 1 1 2 1 + = + + + −+ + + = = + + + −+ + + = + = ∑ TS ST TS TS k ST TS k ST TS TS k ST ST k WWW Уточним звено 2 W для функций ) ( 1 SW и (S) W 2 . Для :)( 1 SW 0.039 3445070.8 6201000000 0.961 3443200 - )1 10 1.8 )( 0.039 10 3.445 ( 0.039 10 3.445 1 10 1.8 1 10 1.8 1 0.039 10 3.445 1 2 3 6 6 3 3 6 2 + ⋅ + ⋅ + ⋅ = = + ⋅ ⋅ + ⋅ ⋅ − ⋅ ⋅ −+ ⋅ ⋅ = + ⋅ ⋅ − + ⋅ ⋅ = S S S S S S S S S W Для :)( 2 SW 0.5 79760900 00 143568000 0.5 79758200 - )1 10 1.8 )( 0.5 10 7.976 ( 0.5 10 7.976 1 10 1.8 1 10 1.8 1 0.5 10 7.976 1 2 3 7 7 3 3 7 2 + ⋅ + ⋅ + ⋅ = = + ⋅ ⋅ + ⋅ ⋅ − ⋅ ⋅ −+ ⋅ ⋅ = + ⋅ ⋅ − + ⋅ ⋅ = S S S S S S S S S W Построим модели в Simulink (рис. 10, 11) и прове- дем моделирование (рис. 12, 13). Рис. 10. Модель, построенная в Simulink Рис. 11. Модель, построенная в Simulink Рис. 12. График выходной величины исходной и эквивалентной функции для звена ) ( 1 SW